Oil Tank Sight-Glass - graduations?

  onthelimit 18:37 PM 07 Sep 10
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I've just had a new plastic oil tank installed. It is cylindrical and lying on its side. It contains 1200 ltrs when full. The sight glass has no markings. I can cope with the half way mark being 600 ltrs, but my maths skills don't help with a few others (useful for ordering the max amount each time to keep the price down). The diameter is 88cm. Can any of those of you good with sums help me get a few more markings on the guage, please? Thanks.

  john bunyan 18:46 PM 07 Sep 10

The volume of a cylinder is ? r squared h, where pi is about 3.142, and the radius is 44cm.Heiht is as you measure to where the top of the oil is at 1200l.
You should be able to calculate the rest.

  john bunyan 18:48 PM 07 Sep 10

the ? above was meant to be the pi symbol, but it did not paste correctly!

  Forum Editor 18:50 PM 07 Sep 10

can you not mark the halfway point, subdivide both sides of it into convenient portions and mark them?

If you divide each half into halves, and then subdivide those you'll end up with 8 graduations representing 75 litres each.

  Forum Editor 18:53 PM 07 Sep 10

I assumed that the sight glass is a vertical glass cylinder.

  onthelimit 19:42 PM 07 Sep 10

As mentioned in the first post, the tank is a cylinder lying on its side, therefore the end where the sight glass is situated is a circle. Half is easy, but the rest is not easily dividable (if there is such a word).

  Forum Editor 19:53 PM 07 Sep 10

I was confused by your original post. You said that the tank was cylindrical and on its side, but you didn't mention that the sight glass was set into one end. Tanks often have vertical glass cylinders as sight glasses, and I made the wrong assumption.

  onthelimit 20:14 PM 07 Sep 10

..but what's the answer?

  Noldi 06:22 AM 08 Sep 10

It’s all about calculating volumes which I think is obvious. You can either divide it evenly and have a idea of what each mark refers to volume wise, I think you need equaled out in volumes . The formula to use is (Angle AOB / 360 deg ) x Pie x r squared. O being center point and A,B being where the triangle meet the radius giving a parallel line across the tank. I will do an Excel sheet at lunch time if I have time.

Noldi

  bri-an 08:39 AM 08 Sep 10

Think you might need the area of segment AB of the circle(major or minor, whichever direction you intend to graduate), as opposed to the sector that you are proposing.

  Quickbeam 08:54 AM 08 Sep 10

If you haven't used it yet, you could use water to make your graduations on the sight glass as you measure it in.

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